# Line slope calculator 3x+5y=35

**Straight line given by points A[5; 4] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.6x+7

**Canonical form of the line equation:**3x+5y-35 = 0

**Parametric form of the line equation:**

x = 5t+5

y = -3t+4 ; t ∈ R

**Slope:**m = -0.6

**Slope angle of line: φ =**-30°57'50″ = -0.5404 rad

**X intercept:**x

_{0}= 11.6667

**Y intercept:**y

_{0}= q = 7

**Distance line from the origin:**d

_{0}= 6.0025

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(5; -3)

**Normal vector: n =**(3; 5)

**Midpoint of the segment AB: M =**[7.5; 2.5]

**Perpendicular Bisector equation:**5x-3y-30 = 0

**Vector OA = (5; 4) ; |OA| = 6.4031**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 54**

**Angle ∠ AOB = 32°56'57″ = 0.5751 rad**